Index: detour/3_hull.html
===================================================================
--- detour/3_hull.html	(revision 896)
+++ detour/3_hull.html	(revision 897)
@@ -80,15 +80,19 @@
 A <i>convex hull of two-net N2</i> [in context of offending object of N1]
 means: the convex hull of all spokes N2, where spoke lengths are calculated
 with D for N1.
+<p>
+A <i>naked convex hull of two-net N2</i> is the convex hull calculated
+using only the centerlines of N2 objects, without considering widths
+or clearances.
 
 <h3> 3.3. Stay-on-layer cases: S1, S2, S3 </h3>
 <p>
-The convex hull of N3 (D set for N1) is calculated so that the the decision
+First the naked convex hull of N3 is calculated so that the the decision
 for S1, S2 or S3 can be made.
 
 <h4> 3.3.1. S1: both ends outside </h4>
 <p>
-Both ends of the offending line object of N1 are outside of the convex hull
+Both ends of the offending line object of N1 are outside of the naked convex hull
 of N3. The two possible detour paths are calculated as:
 <ul>
 	<li> collect all spoke endpoints of N3, add the two endpoints of the offending trace line object of N1
@@ -135,11 +139,11 @@
 
 <h4> 3.3.2. S2: One end outside </h4>
 <p>
-One end of the offending line object of N1 is outside of the convex hull
+One end of the offending line object of N1 is outside of the naked convex hull
 of N3, the other end is inside (Figure 3/5, marked P0). The two possible
 detour paths are calculated as:
 <ul>
-	<li> calculate a new convex hull of N3 with the offending line outside endpoint (P4) included
+	<li> calculate a convex hull of N3 with the offending line outside endpoint (P4) included
 	<li> find a section of the convex hull of N3 that has a direct line of visibility from the offending object endpoint that is inside
 	<li> the direct line of sight may not cross spokes of N3
 	<li> split the hull in two:
@@ -164,12 +168,13 @@
 
 <h4> 3.3.3. S3: Both ends inside </h4>
 <p>
-Both ends of the offending line object of N1 is inside of the convex hull
+Both ends of the offending line object of N1 is inside of the naked convex hull
 of N3 (Figure 3/6). There is only one possible detour path.
 <p>
 First collect the N3 corners that are contributing the violation:
 <ul>
 	<li> if the offending N1 line crosses any N3 objects, the corners of those N3 objects that are between the two crossings are added (Figure 3/6, b)
+	     (TODO: this doesn't handle junctions, polygons and generally things that are hanging inside N3 from the wall!)
 	<li> in such crossing, also add the crossing points (Figure 3/6, b)
 	<li> if the offending N1 line is getting too close to any corner of N3, add those corners too (Figure 3/6, e)
 	<li> always add both endponits of the offending N1 line
@@ -185,7 +190,7 @@
 <p>
 Once those corners are collected, the path calculation is:
 <ul>
-	<li> calculate a new convex hull using the above corners and their N3-N1 spokes
+	<li> calculate a convex hull using the above corners and their N3-N1 spokes
 	<li> split the hull in two at the offending line endpoints
 	<li> one half will cross N3 - throw it away
 	<li> the other half is the resulting path; replace the offending line with this path